Base | Representation |
---|---|
bin | 11101110010010100100011… |
… | …111110100100011011100111 |
3 | 122011211121111212211222010201 |
4 | 131302110203332210123213 |
5 | 114132311332140200012 |
6 | 1142341113550531331 |
7 | 36410352561464254 |
oct | 3562244376443347 |
9 | 564747455758121 |
10 | 131001401100007 |
11 | 388174227a3309 |
12 | 12838b48206b47 |
13 | 58134c0bc6089 |
14 | 244c70472242b |
15 | 10229a8d20857 |
hex | 772523fa46e7 |
131001401100007 has 2 divisors, whose sum is σ = 131001401100008. Its totient is φ = 131001401100006.
The previous prime is 131001401099963. The next prime is 131001401100019. The reversal of 131001401100007 is 700001104100131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001401100007 - 27 = 131001401099879 is a prime.
It is a super-2 number, since 2×1310014011000072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001401100067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500700550003 + 65500700550004.
It is an arithmetic number, because the mean of its divisors is an integer number (65500700550004).
Almost surely, 2131001401100007 is an apocalyptic number.
131001401100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001401100007 is an equidigital number, since it uses as much as digits as its factorization.
131001401100007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 131001401100007 its reverse (700001104100131), we get a palindrome (831002505200138).
The spelling of 131001401100007 in words is "one hundred thirty-one trillion, one billion, four hundred one million, one hundred thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •