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131001401100003 = 379617964859917
BaseRepresentation
bin11101110010010100100011…
…111110100100011011100011
3122011211121111212211222010120
4131302110203332210123203
5114132311332140200003
61142341113550531323
736410352561464250
oct3562244376443343
9564747455758116
10131001401100003
11388174227a3305
1212838b48206b43
1358134c0bc6085
14244c704722427
1510229a8d20853
hex772523fa46e3

131001401100003 has 16 divisors (see below), whose sum is σ = 199623261223680. Its totient is φ = 74857164012576.

The previous prime is 131001401099963. The next prime is 131001401100007. The reversal of 131001401100003 is 300001104100131.

It is not a de Polignac number, because 131001401100003 - 28 = 131001401099747 is a prime.

It is a super-2 number, since 2×1310014011000032 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131001401100007) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30410200 + ... + 34449717.

It is an arithmetic number, because the mean of its divisors is an integer number (12476453826480).

Almost surely, 2131001401100003 is an apocalyptic number.

131001401100003 is a deficient number, since it is larger than the sum of its proper divisors (68621860123677).

131001401100003 is an equidigital number, since it uses as much as digits as its factorization.

131001401100003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64956106.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 131001401100003 its reverse (300001104100131), we get a palindrome (431002505200134).

The spelling of 131001401100003 in words is "one hundred thirty-one trillion, one billion, four hundred one million, one hundred thousand, three".

Divisors: 1 3 7 21 96179 288537 673253 2019759 64859917 194579751 454019419 1362058257 6238161957143 18714485871429 43667133700001 131001401100003