131001401114341 has 4 divisors (see below), whose sum is σ = 131009719207500. Its totient is φ = 130993083021184.

The previous prime is 131001401114291. The next prime is 131001401114431. The reversal of 131001401114341 is 143411104100131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 53175393285316 + 77826007829025 = 7292146^2 + 8821905^2 .

It is a cyclic number.

It is not a de Polignac number, because 131001401114341 - 2²¹ = 131001399017189 is a prime.

It is a super-2 number, since 2×131001401114341² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131001401114141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4159022956 + ... + 4159054453.

It is an arithmetic number, because the mean of its divisors is an integer number (32752429801875).

Almost surely, 2^{131001401114341} is an apocalyptic number.

It is an amenable number.

131001401114341 is a deficient number, since it is larger than the sum of its proper divisors (8318093159).

131001401114341 is an equidigital number, since it uses as much as digits as its factorization.

131001401114341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8318093158.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131001401114341 its reverse (143411104100131), we get a palindrome (274412505214472).

The spelling of 131001401114341 in words is "one hundred thirty-one trillion, one billion, four hundred one million, one hundred fourteen thousand, three hundred forty-one".