13100142412121 has 4 divisors (see below), whose sum is σ = 13103411730432. Its totient is φ = 13096873093812.

The previous prime is 13100142412117. The next prime is 13100142412139. The reversal of 13100142412121 is 12121424100131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100142412121 - 2² = 13100142412117 is a prime.

It is a super-2 number, since 2×13100142412121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100142411121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1634653145 + ... + 1634661158.

It is an arithmetic number, because the mean of its divisors is an integer number (3275852932608).

Almost surely, 2^{13100142412121} is an apocalyptic number.

It is an amenable number.

13100142412121 is a deficient number, since it is larger than the sum of its proper divisors (3269318311).

13100142412121 is an equidigital number, since it uses as much as digits as its factorization.

13100142412121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3269318310.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 13100142412121 its reverse (12121424100131), we get a palindrome (25221566512252).

The spelling of 13100142412121 in words is "thirteen trillion, one hundred billion, one hundred forty-two million, four hundred twelve thousand, one hundred twenty-one".