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13100151053351 = 36462135928131
BaseRepresentation
bin1011111010100001110111…
…0110011001110000100111
31201101100210001101011202202
42332220131312121300213
53204113102132201401
643510043141125115
72521311645454565
oct276503566316047
951340701334682
1013100151053351
1141a081982747a
121576a920b979b
1374045387532b
1433409d166a35
1517ab71cad06b
hexbea1dd99c27

13100151053351 has 4 divisors (see below), whose sum is σ = 13100187346104. Its totient is φ = 13100114760600.

The previous prime is 13100151053323. The next prime is 13100151053357. The reversal of 13100151053351 is 15335015100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13100151053351 - 26 = 13100151053287 is a prime.

It is a super-2 number, since 2×131001510533512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100151053357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17599445 + ... + 18328686.

It is an arithmetic number, because the mean of its divisors is an integer number (3275046836526).

Almost surely, 213100151053351 is an apocalyptic number.

13100151053351 is a deficient number, since it is larger than the sum of its proper divisors (36292753).

13100151053351 is an equidigital number, since it uses as much as digits as its factorization.

13100151053351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36292752.

The product of its (nonzero) digits is 3375, while the sum is 29.

Adding to 13100151053351 its reverse (15335015100131), we get a palindrome (28435166153482).

The spelling of 13100151053351 in words is "thirteen trillion, one hundred billion, one hundred fifty-one million, fifty-three thousand, three hundred fifty-one".

Divisors: 1 364621 35928131 13100151053351