Base | Representation |
---|---|
bin | 10011000100000011001… |
… | …001110110110011101101 |
3 | 11122020101101212120101112 |
4 | 103010003021312303231 |
5 | 132430404043100332 |
6 | 2441451450521405 |
7 | 163434315524543 |
oct | 23040311666355 |
9 | 4566341776345 |
10 | 1310017940717 |
11 | 465636a80342 |
12 | 191a82436265 |
13 | 966c3726905 |
14 | 47595c5bd93 |
15 | 24123678db2 |
hex | 13103276ced |
1310017940717 has 2 divisors, whose sum is σ = 1310017940718. Its totient is φ = 1310017940716.
The previous prime is 1310017940713. The next prime is 1310017940783. The reversal of 1310017940717 is 7170497100131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 734575841476 + 575442099241 = 857074^2 + 758579^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310017940717 - 22 = 1310017940713 is a prime.
It is a super-2 number, since 2×13100179407172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310017940713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655008970358 + 655008970359.
It is an arithmetic number, because the mean of its divisors is an integer number (655008970359).
Almost surely, 21310017940717 is an apocalyptic number.
It is an amenable number.
1310017940717 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310017940717 is an equidigital number, since it uses as much as digits as its factorization.
1310017940717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37044, while the sum is 41.
The spelling of 1310017940717 in words is "one trillion, three hundred ten billion, seventeen million, nine hundred forty thousand, seven hundred seventeen".
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