Base | Representation |
---|---|
bin | 10011000100000011010… |
… | …001101101100101101111 |
3 | 11122020101112202012100101 |
4 | 103010003101231211233 |
5 | 132430410110000421 |
6 | 2441452003011531 |
7 | 163434342162604 |
oct | 23040321554557 |
9 | 4566345665311 |
10 | 1310020000111 |
11 | 465638157619 |
12 | 191a83069ba7 |
13 | 966c3c980a4 |
14 | 475962366ab |
15 | 24123934191 |
hex | 1310346d96f |
1310020000111 has 4 divisors (see below), whose sum is σ = 1352278709824. Its totient is φ = 1267761290400.
The previous prime is 1310020000103. The next prime is 1310020000141. The reversal of 1310020000111 is 1110000200131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310020000111 - 23 = 1310020000103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310020000141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21129354810 + ... + 21129354871.
It is an arithmetic number, because the mean of its divisors is an integer number (338069677456).
Almost surely, 21310020000111 is an apocalyptic number.
1310020000111 is a deficient number, since it is larger than the sum of its proper divisors (42258709713).
1310020000111 is an equidigital number, since it uses as much as digits as its factorization.
1310020000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42258709712.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 1310020000111 its reverse (1110000200131), we get a palindrome (2420020200242).
The spelling of 1310020000111 in words is "one trillion, three hundred ten billion, twenty million, one hundred eleven", and thus it is an aban number.
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