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1310020023313 = 1458238983631
BaseRepresentation
bin10011000100000011010…
…001110011010000010001
311122020101112210101011201
4103010003101303100101
5132430410111221223
62441452003311201
7163434342320341
oct23040321632021
94566345711151
101310020023313
11465638172aa1
12191a8307b501
13966c3ca5811
1447596240d21
152412393aead
hex13103473411

1310020023313 has 4 divisors (see below), whose sum is σ = 1310029152768. Its totient is φ = 1310010893860.

The previous prime is 1310020023271. The next prime is 1310020023353. The reversal of 1310020023313 is 3133200200131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310020023313 - 237 = 1172581069841 is a prime.

It is a super-2 number, since 2×13100200233132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310020023353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4345993 + ... + 4637638.

It is an arithmetic number, because the mean of its divisors is an integer number (327507288192).

Almost surely, 21310020023313 is an apocalyptic number.

It is an amenable number.

1310020023313 is a deficient number, since it is larger than the sum of its proper divisors (9129455).

1310020023313 is an equidigital number, since it uses as much as digits as its factorization.

1310020023313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9129454.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1310020023313 its reverse (3133200200131), we get a palindrome (4443220223444).

The spelling of 1310020023313 in words is "one trillion, three hundred ten billion, twenty million, twenty-three thousand, three hundred thirteen".

Divisors: 1 145823 8983631 1310020023313