1310020220023 has 4 divisors (see below), whose sum is σ = 1310605313920. Its totient is φ = 1309435126128.

The previous prime is 1310020220017. The next prime is 1310020220029. The reversal of 1310020220023 is 3200220200131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1310020220017) and next prime (1310020220029).

It is a cyclic number.

It is not a de Polignac number, because 1310020220023 - 2¹³ = 1310020211831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310020219979 and 1310020220006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310020220029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292543590 + ... + 292548067.

It is an arithmetic number, because the mean of its divisors is an integer number (327651328480).

Almost surely, 2^{1310020220023} is an apocalyptic number.

1310020220023 is a deficient number, since it is larger than the sum of its proper divisors (585093897).

1310020220023 is an equidigital number, since it uses as much as digits as its factorization.

1310020220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 585093896.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 1310020220023 its reverse (3200220200131), we get a palindrome (4510240420154).

The spelling of 1310020220023 in words is "one trillion, three hundred ten billion, twenty million, two hundred twenty thousand, twenty-three".