Base | Representation |
---|---|
bin | 11101110010010101001111… |
… | …100100000000000111001001 |
3 | 122011211200101211210110020012 |
4 | 131302111033210000013021 |
5 | 114132314331334124001 |
6 | 1142341314311441305 |
7 | 36410406651041006 |
oct | 3562251744000711 |
9 | 564750354713205 |
10 | 131002132333001 |
11 | 388177685354a6 |
12 | 12839111086235 |
13 | 58135a954c717 |
14 | 244c7738aa8ad |
15 | 10229ed1122bb |
hex | 77254f9001c9 |
131002132333001 has 2 divisors, whose sum is σ = 131002132333002. Its totient is φ = 131002132333000.
The previous prime is 131002132332857. The next prime is 131002132333043. The reversal of 131002132333001 is 100333231200131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129329753160976 + 1672379172025 = 11372324^2 + 1293205^2 .
It is a cyclic number.
It is not a de Polignac number, because 131002132333001 - 218 = 131002132070857 is a prime.
It is not a weakly prime, because it can be changed into another prime (131002132333091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501066166500 + 65501066166501.
It is an arithmetic number, because the mean of its divisors is an integer number (65501066166501).
Almost surely, 2131002132333001 is an apocalyptic number.
It is an amenable number.
131002132333001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131002132333001 is an equidigital number, since it uses as much as digits as its factorization.
131002132333001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 131002132333001 its reverse (100333231200131), we get a palindrome (231335363533132).
The spelling of 131002132333001 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-two million, three hundred thirty-three thousand, one".
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