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131002320041 is a prime number
BaseRepresentation
bin111101000000001011…
…0001100010010101001
3110112010202222101020022
41322000112030102221
54121243043220131
6140103122210225
712315234230135
oct1720026142251
9415122871208
10131002320041
1150615437aaa
12214804b3975
13c479744a08
1464aa65c3c5
15361ad5237b
hex1e8058c4a9

131002320041 has 2 divisors, whose sum is σ = 131002320042. Its totient is φ = 131002320040.

The previous prime is 131002320019. The next prime is 131002320047. The reversal of 131002320041 is 140023200131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103617034816 + 27385285225 = 321896^2 + 165485^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131002320041 is a prime.

It is a super-2 number, since 2×1310023200412 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131002320047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501160020 + 65501160021.

It is an arithmetic number, because the mean of its divisors is an integer number (65501160021).

Almost surely, 2131002320041 is an apocalyptic number.

It is an amenable number.

131002320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002320041 is an equidigital number, since it uses as much as digits as its factorization.

131002320041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 131002320041 its reverse (140023200131), we get a palindrome (271025520172).

The spelling of 131002320041 in words is "one hundred thirty-one billion, two million, three hundred twenty thousand, forty-one".