Base | Representation |
---|---|
bin | 1011111010100010001101… |
… | …1010001110101011010111 |
3 | 1201101101000112220011221202 |
4 | 2332220203122032223113 |
5 | 3204113300022044343 |
6 | 43510100312303115 |
7 | 2521314160352000 |
oct | 276504332165327 |
9 | 51341015804852 |
10 | 13100244331223 |
11 | 41a0867447525 |
12 | 1576ab93a1a9b |
13 | 740469ca423a |
14 | 3340ab6c81a7 |
15 | 17ab7a085db8 |
hex | bea2368ead7 |
13100244331223 has 16 divisors (see below), whose sum is σ = 16175914804800. Its totient is φ = 10568264329728.
The previous prime is 13100244331199. The next prime is 13100244331243. The reversal of 13100244331223 is 32213344200131.
It is not a de Polignac number, because 13100244331223 - 232 = 13095949363927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100244331243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1123321586 + ... + 1123333247.
It is an arithmetic number, because the mean of its divisors is an integer number (1010994675300).
Almost surely, 213100244331223 is an apocalyptic number.
13100244331223 is a deficient number, since it is larger than the sum of its proper divisors (3075670473577).
13100244331223 is an equidigital number, since it uses as much as digits as its factorization.
13100244331223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2246654871 (or 2246654857 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13100244331223 its reverse (32213344200131), we get a palindrome (45313588531354).
The spelling of 13100244331223 in words is "thirteen trillion, one hundred billion, two hundred forty-four million, three hundred thirty-one thousand, two hundred twenty-three".
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