13100253202 has 4 divisors (see below), whose sum is σ = 19650379806. Its totient is φ = 6550126600.

The previous prime is 13100253197. The next prime is 13100253253. The reversal of 13100253202 is 20235200131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13080725641 + 19527561 = 114371^2 + 4419^2 .

It is a super-2 number, since 2×13100253202² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13100253202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275063299 + ... + 3275063302.

Almost surely, 2^13100253202 is an apocalyptic number.

13100253202 is a deficient number, since it is larger than the sum of its proper divisors (6550126604).

13100253202 is an equidigital number, since it uses as much as digits as its factorization.

13100253202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6550126603.

The product of its (nonzero) digits is 360, while the sum is 19.

Adding to 13100253202 its reverse (20235200131), we get a palindrome (33335453333).

The spelling of 13100253202 in words is "thirteen billion, one hundred million, two hundred fifty-three thousand, two hundred two".