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131002665276557 is a prime number
BaseRepresentation
bin11101110010010101101111…
…010101000001010010001101
3122011211201202222121210100102
4131302111233111001102031
5114132321424302322212
61142341443230340445
736410426112013214
oct3562255725012215
9564751688553312
10131002665276557
1138817a11352918
121283923b65a725
135813662a9a539
14244c7c459a07b
151022a2ecd65c2
hex77256f54148d

131002665276557 has 2 divisors, whose sum is σ = 131002665276558. Its totient is φ = 131002665276556.

The previous prime is 131002665276473. The next prime is 131002665276611. The reversal of 131002665276557 is 755672566200131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100211031218116 + 30791634058441 = 10010546^2 + 5549021^2 .

It is a cyclic number.

It is not a de Polignac number, because 131002665276557 - 246 = 60633921098893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131022665276557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501332638278 + 65501332638279.

It is an arithmetic number, because the mean of its divisors is an integer number (65501332638279).

Almost surely, 2131002665276557 is an apocalyptic number.

It is an amenable number.

131002665276557 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002665276557 is an equidigital number, since it uses as much as digits as its factorization.

131002665276557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876000, while the sum is 56.

The spelling of 131002665276557 in words is "one hundred thirty-one trillion, two billion, six hundred sixty-five million, two hundred seventy-six thousand, five hundred fifty-seven".