Base | Representation |
---|---|
bin | 1011111010100010011010… |
… | …1111011100011000000011 |
3 | 1201101101011110001211102201 |
4 | 2332220212233130120003 |
5 | 3204113403324132003 |
6 | 43510110030254031 |
7 | 2521315436421466 |
oct | 276504657343003 |
9 | 51341143054381 |
10 | 13100300224003 |
11 | 41a0895a52603 |
12 | 1576b14057317 |
13 | 7404787438a5 |
14 | 3340b4cb72dd |
15 | 17ab7ee26b1d |
hex | bea26bdc603 |
13100300224003 has 2 divisors, whose sum is σ = 13100300224004. Its totient is φ = 13100300224002.
The previous prime is 13100300223943. The next prime is 13100300224021. The reversal of 13100300224003 is 30042200300131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13100300224003 - 213 = 13100300215811 is a prime.
It is not a weakly prime, because it can be changed into another prime (13100300224043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550150112001 + 6550150112002.
It is an arithmetic number, because the mean of its divisors is an integer number (6550150112002).
Almost surely, 213100300224003 is an apocalyptic number.
13100300224003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100300224003 is an equidigital number, since it uses as much as digits as its factorization.
13100300224003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13100300224003 its reverse (30042200300131), we get a palindrome (43142500524134).
The spelling of 13100300224003 in words is "thirteen trillion, one hundred billion, three hundred million, two hundred twenty-four thousand, three".
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