Base | Representation |
---|---|
bin | 11101110010010110000011… |
… | …111101000111010001110101 |
3 | 122011211202200002210012001122 |
4 | 131302112003331013101311 |
5 | 114132323131400044224 |
6 | 1142341541431433325 |
7 | 36410440513305644 |
oct | 3562260375072165 |
9 | 564752602705048 |
10 | 131003011331189 |
11 | 38818079722888 |
12 | 12839317525845 |
13 | 58136b96a19aa |
14 | 244c81851b35b |
15 | 1022a5039115e |
hex | 772583f47475 |
131003011331189 has 2 divisors, whose sum is σ = 131003011331190. Its totient is φ = 131003011331188.
The previous prime is 131003011331167. The next prime is 131003011331239. The reversal of 131003011331189 is 981133110300131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 123098647770289 + 7904363560900 = 11094983^2 + 2811470^2 .
It is a cyclic number.
It is not a de Polignac number, because 131003011331189 - 240 = 129903499703413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131003011330189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501505665594 + 65501505665595.
It is an arithmetic number, because the mean of its divisors is an integer number (65501505665595).
Almost surely, 2131003011331189 is an apocalyptic number.
It is an amenable number.
131003011331189 is a deficient number, since it is larger than the sum of its proper divisors (1).
131003011331189 is an equidigital number, since it uses as much as digits as its factorization.
131003011331189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 131003011331189 in words is "one hundred thirty-one trillion, three billion, eleven million, three hundred thirty-one thousand, one hundred eighty-nine".
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