Base | Representation |
---|---|
bin | 11101110010010110000011… |
… | …111101000111010010001010 |
3 | 122011211202200002210012002102 |
4 | 131302112003331013102022 |
5 | 114132323131400044320 |
6 | 1142341541431433402 |
7 | 36410440513306004 |
oct | 3562260375072212 |
9 | 564752602705072 |
10 | 131003011331210 |
11 | 388180797228a7 |
12 | 12839317525862 |
13 | 58136b96a19c5 |
14 | 244c81851b374 |
15 | 1022a50391175 |
hex | 772583f4748a |
131003011331210 has 32 divisors (see below), whose sum is σ = 240842826593280. Its totient is φ = 51281968614912.
The previous prime is 131003011331189. The next prime is 131003011331239. The reversal of 131003011331210 is 12133110300131.
It is a super-4 number, since 4×1310030113312104 (a number of 58 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6137255 + ... + 17311034.
It is an arithmetic number, because the mean of its divisors is an integer number (7526338331040).
Almost surely, 2131003011331210 is an apocalyptic number.
131003011331210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131003011331210 is a deficient number, since it is larger than the sum of its proper divisors (109839815262070).
131003011331210 is a wasteful number, since it uses less digits than its factorization.
131003011331210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23460230.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 131003011331210 its reverse (12133110300131), we get a palindrome (143136121631341).
The spelling of 131003011331210 in words is "one hundred thirty-one trillion, three billion, eleven million, three hundred thirty-one thousand, two hundred ten".
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