Base | Representation |
---|---|
bin | 11000011001101011… |
… | …01011111011001111 |
3 | 1020210222112021222112 |
4 | 30030311223323033 |
5 | 203312134131111 |
6 | 10003532534235 |
7 | 642431505245 |
oct | 141465537317 |
9 | 36728467875 |
10 | 13100302031 |
11 | 56128628a3 |
12 | 265732137b |
13 | 130a0bcb0b |
14 | 8c3bd8795 |
15 | 51a165e8b |
hex | 30cd6becf |
13100302031 has 2 divisors, whose sum is σ = 13100302032. Its totient is φ = 13100302030.
The previous prime is 13100301971. The next prime is 13100302043. The reversal of 13100302031 is 13020300131.
It is a strong prime.
It is an emirp because it is prime and its reverse (13020300131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13100302031 - 26 = 13100301967 is a prime.
It is a super-2 number, since 2×131003020312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100301997 and 13100302015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100392031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550151015 + 6550151016.
It is an arithmetic number, because the mean of its divisors is an integer number (6550151016).
Almost surely, 213100302031 is an apocalyptic number.
13100302031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100302031 is an equidigital number, since it uses as much as digits as its factorization.
13100302031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13100302031 its reverse (13020300131), we get a palindrome (26120602162).
The spelling of 13100302031 in words is "thirteen billion, one hundred million, three hundred two thousand, thirty-one".
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