131003031113 has 4 divisors (see below), whose sum is σ = 131003825940. Its totient is φ = 131002236288.

The previous prime is 131003031109. The next prime is 131003031119. The reversal of 131003031113 is 311130300131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 128026564864 + 2976466249 = 357808^2 + 54557^2 .

It is a cyclic number.

It is not a de Polignac number, because 131003031113 - 2² = 131003031109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131003031091 and 131003031100.

It is not an unprimeable number, because it can be changed into a prime (131003031119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47468 + ... + 514061.

It is an arithmetic number, because the mean of its divisors is an integer number (32750956485).

Almost surely, 2^131003031113 is an apocalyptic number.

It is an amenable number.

131003031113 is a deficient number, since it is larger than the sum of its proper divisors (794827).

131003031113 is an equidigital number, since it uses as much as digits as its factorization.

131003031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794826.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131003031113 its reverse (311130300131), we get a palindrome (442133331244).

The spelling of 131003031113 in words is "one hundred thirty-one billion, three million, thirty-one thousand, one hundred thirteen".