Base | Representation |
---|---|
bin | 10011000100000011111… |
… | …011110101001110001110 |
3 | 11122020102022112011011211 |
4 | 103010003323311032032 |
5 | 132430420421311142 |
6 | 2441453035405034 |
7 | 163434535060165 |
oct | 23040373651616 |
9 | 4566368464154 |
10 | 1310031041422 |
11 | 465643409074 |
12 | 191a868b377a |
13 | 966c63628cc |
14 | 475978ac3dc |
15 | 241248b5917 |
hex | 13103ef538e |
1310031041422 has 4 divisors (see below), whose sum is σ = 1965046562136. Its totient is φ = 655015520710.
The previous prime is 1310031041413. The next prime is 1310031041453. The reversal of 1310031041422 is 2241401300131.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1310031041393 and 1310031041402.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327507760354 + ... + 327507760357.
It is an arithmetic number, because the mean of its divisors is an integer number (491261640534).
Almost surely, 21310031041422 is an apocalyptic number.
1310031041422 is a deficient number, since it is larger than the sum of its proper divisors (655015520714).
1310031041422 is an equidigital number, since it uses as much as digits as its factorization.
1310031041422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655015520713.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1310031041422 its reverse (2241401300131), we get a palindrome (3551432341553).
The spelling of 1310031041422 in words is "one trillion, three hundred ten billion, thirty-one million, forty-one thousand, four hundred twenty-two".
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