Base | Representation |
---|---|
bin | 1011111010100010011101… |
… | …1000101000101011100111 |
3 | 1201101101012012101102221001 |
4 | 2332220213120220223213 |
5 | 3204113414110203221 |
6 | 43510111053534131 |
7 | 2521315630254442 |
oct | 276504730505347 |
9 | 51341165342831 |
10 | 13100311022311 |
11 | 41a08a1058527 |
12 | 1576b177a4347 |
13 | 74047aa54916 |
14 | 3340b64c8659 |
15 | 17ab80d5b391 |
hex | bea27628ae7 |
13100311022311 has 4 divisors (see below), whose sum is σ = 13100420596752. Its totient is φ = 13100201447872.
The previous prime is 13100311022287. The next prime is 13100311022321. The reversal of 13100311022311 is 11322011300131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13100311022311 - 215 = 13100310989543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100311022321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54607690 + ... + 54847063.
It is an arithmetic number, because the mean of its divisors is an integer number (3275105149188).
Almost surely, 213100311022311 is an apocalyptic number.
13100311022311 is a deficient number, since it is larger than the sum of its proper divisors (109574441).
13100311022311 is a wasteful number, since it uses less digits than its factorization.
13100311022311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109574440.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13100311022311 its reverse (11322011300131), we get a palindrome (24422322322442).
The spelling of 13100311022311 in words is "thirteen trillion, one hundred billion, three hundred eleven million, twenty-two thousand, three hundred eleven".
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