Base | Representation |
---|---|
bin | 11101110010010110001010… |
… | …000010000110010011010011 |
3 | 122011211202221012122210121211 |
4 | 131302112022002012103103 |
5 | 114132323334001114303 |
6 | 1142341555513200551 |
7 | 36410443162114423 |
oct | 3562261202062323 |
9 | 564752835583554 |
10 | 131003113301203 |
11 | 3881812123a420 |
12 | 12839345700157 |
13 | 5813704855090 |
14 | 244c827ca2483 |
15 | 1022a592d466d |
hex | 77258a0864d3 |
131003113301203 has 16 divisors (see below), whose sum is σ = 153917773077600. Its totient is φ = 109924098497280.
The previous prime is 131003113301189. The next prime is 131003113301209. The reversal of 131003113301203 is 302103311300131.
It is a cyclic number.
It is not a de Polignac number, because 131003113301203 - 221 = 131003111204051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131003113301209) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33928548 + ... + 37591921.
It is an arithmetic number, because the mean of its divisors is an integer number (9619860817350).
Almost surely, 2131003113301203 is an apocalyptic number.
131003113301203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
131003113301203 is a deficient number, since it is larger than the sum of its proper divisors (22914659776397).
131003113301203 is a wasteful number, since it uses less digits than its factorization.
131003113301203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71533302.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 131003113301203 its reverse (302103311300131), we get a palindrome (433106424601334).
The spelling of 131003113301203 in words is "one hundred thirty-one trillion, three billion, one hundred thirteen million, three hundred one thousand, two hundred three".
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