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131003120003 = 719519592379
BaseRepresentation
bin111101000000001100…
…1001111100110000011
3110112010211111000120112
41322000121033212003
54121243244320003
6140103151301535
712315244101320
oct1720031174603
9415124430515
10131003120003
1150615934028
122148081a8ab
13c479964b72
1464aa7c9b47
15361ae5e3d8
hex1e8064f983

131003120003 has 8 divisors (see below), whose sum is σ = 149794606080. Its totient is φ = 112230822600.

The previous prime is 131003119997. The next prime is 131003120023. The reversal of 131003120003 is 300021300131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131003120003 - 24 = 131003119987 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131003120003.

It is not an unprimeable number, because it can be changed into a prime (131003120023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4782533 + ... + 4809846.

It is an arithmetic number, because the mean of its divisors is an integer number (18724325760).

Almost surely, 2131003120003 is an apocalyptic number.

131003120003 is a deficient number, since it is larger than the sum of its proper divisors (18791486077).

131003120003 is an equidigital number, since it uses as much as digits as its factorization.

131003120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9594337.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 131003120003 its reverse (300021300131), we get a palindrome (431024420134).

The spelling of 131003120003 in words is "one hundred thirty-one billion, three million, one hundred twenty thousand, three".

Divisors: 1 7 1951 13657 9592379 67146653 18714731429 131003120003