13100313301 has 4 divisors (see below), whose sum is σ = 13100566912. Its totient is φ = 13100059692.

The previous prime is 13100313299. The next prime is 13100313313. The reversal of 13100313301 is 10331300131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10331300131 = 1823 ⋅5667197.

It is a cyclic number.

It is not a de Polignac number, because 13100313301 - 2¹ = 13100313299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100313341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18471 + ... + 162916.

It is an arithmetic number, because the mean of its divisors is an integer number (3275141728).

Almost surely, 2^13100313301 is an apocalyptic number.

It is an amenable number.

13100313301 is a deficient number, since it is larger than the sum of its proper divisors (253611).

13100313301 is an equidigital number, since it uses as much as digits as its factorization.

13100313301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 253610.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13100313301 its reverse (10331300131), we get a palindrome (23431613432).

The spelling of 13100313301 in words is "thirteen billion, one hundred million, three hundred thirteen thousand, three hundred one".