13100321424301 has 4 divisors (see below), whose sum is σ = 13789812025600. Its totient is φ = 12410830823004.

The previous prime is 13100321424269. The next prime is 13100321424331. The reversal of 13100321424301 is 10342412300131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100321424301 - 2⁵ = 13100321424269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100321424331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 344745300621 + ... + 344745300658.

It is an arithmetic number, because the mean of its divisors is an integer number (3447453006400).

Almost surely, 2^{13100321424301} is an apocalyptic number.

It is an amenable number.

13100321424301 is a deficient number, since it is larger than the sum of its proper divisors (689490601299).

13100321424301 is an equidigital number, since it uses as much as digits as its factorization.

13100321424301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 689490601298.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13100321424301 its reverse (10342412300131), we get a palindrome (23442733724432).

The spelling of 13100321424301 in words is "thirteen trillion, one hundred billion, three hundred twenty-one million, four hundred twenty-four thousand, three hundred one".