Base | Representation |
---|---|
bin | 1011111010100010100000… |
… | …0011101100111111000100 |
3 | 1201101101012222122000122120 |
4 | 2332220220003230333010 |
5 | 3204113430002442012 |
6 | 43510112135525540 |
7 | 2521316125235406 |
oct | 276505003547704 |
9 | 51341188560576 |
10 | 13100322312132 |
11 | 41a08a7469760 |
12 | 1576b1b5298b0 |
13 | 7404801a85a3 |
14 | 3340b7bc6b76 |
15 | 17ab81d3b58c |
hex | bea280ecfc4 |
13100322312132 has 24 divisors (see below), whose sum is σ = 33346274976672. Its totient is φ = 3969794640000.
The previous prime is 13100322312097. The next prime is 13100322312227. The reversal of 13100322312132 is 23121322300131.
13100322312132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49622432869 + ... + 49622433132.
It is an arithmetic number, because the mean of its divisors is an integer number (1389428124028).
Almost surely, 213100322312132 is an apocalyptic number.
13100322312132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13100322312132 is an abundant number, since it is smaller than the sum of its proper divisors (20245952664540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100322312132 is a wasteful number, since it uses less digits than its factorization.
13100322312132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99244866019 (or 99244866017 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13100322312132 its reverse (23121322300131), we get a palindrome (36221644612263).
The spelling of 13100322312132 in words is "thirteen trillion, one hundred billion, three hundred twenty-two million, three hundred twelve thousand, one hundred thirty-two".
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