Base | Representation |
---|---|
bin | 1011111010100010100000… |
… | …0110011111101111110111 |
3 | 1201101101020001000020001111 |
4 | 2332220220012133233313 |
5 | 3204113430144404333 |
6 | 43510112203335451 |
7 | 2521316134405213 |
oct | 276505006375767 |
9 | 51341201006044 |
10 | 13100323044343 |
11 | 41a08a7919897 |
12 | 1576b1b821587 |
13 | 7404803a3952 |
14 | 3340b7d37943 |
15 | 17ab81e334cd |
hex | bea2819fbf7 |
13100323044343 has 2 divisors, whose sum is σ = 13100323044344. Its totient is φ = 13100323044342.
The previous prime is 13100323044301. The next prime is 13100323044359. The reversal of 13100323044343 is 34344032300131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13100323044343 is a prime.
It is a super-2 number, since 2×131003230443432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100323044143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550161522171 + 6550161522172.
It is an arithmetic number, because the mean of its divisors is an integer number (6550161522172).
Almost surely, 213100323044343 is an apocalyptic number.
13100323044343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100323044343 is an equidigital number, since it uses as much as digits as its factorization.
13100323044343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13100323044343 its reverse (34344032300131), we get a palindrome (47444355344474).
The spelling of 13100323044343 in words is "thirteen trillion, one hundred billion, three hundred twenty-three million, forty-four thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •