13100340432181 has 2 divisors, whose sum is σ = 13100340432182. Its totient is φ = 13100340432180.

The previous prime is 13100340432079. The next prime is 13100340432187. The reversal of 13100340432181 is 18123404300131.

13100340432181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6731611866225 + 6368728565956 = 2594535^2 + 2523634^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100340432181 - 2³⁵ = 13065980693813 is a prime.

It is a super-2 number, since 2×13100340432181² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100340432187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550170216090 + 6550170216091.

It is an arithmetic number, because the mean of its divisors is an integer number (6550170216091).

Almost surely, 2^{13100340432181} is an apocalyptic number.

It is an amenable number.

13100340432181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100340432181 is an equidigital number, since it uses as much as digits as its factorization.

13100340432181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 13100340432181 in words is "thirteen trillion, one hundred billion, three hundred forty million, four hundred thirty-two thousand, one hundred eighty-one".