Base | Representation |
---|---|
bin | 111101000000001101… |
… | …0110000000010101011 |
3 | 110112010212020002110221 |
4 | 1322000122300002223 |
5 | 4121243344440201 |
6 | 140103203550511 |
7 | 12315250335133 |
oct | 1720032600253 |
9 | 415125202427 |
10 | 131003515051 |
11 | 50616083912 |
12 | 2148098b437 |
13 | c479a72916 |
14 | 64aa88dac3 |
15 | 361aedb4a1 |
hex | 1e806b00ab |
131003515051 has 2 divisors, whose sum is σ = 131003515052. Its totient is φ = 131003515050.
The previous prime is 131003515043. The next prime is 131003515103. The reversal of 131003515051 is 150515300131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131003515051 - 23 = 131003515043 is a prime.
It is not a weakly prime, because it can be changed into another prime (131003515031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501757525 + 65501757526.
It is an arithmetic number, because the mean of its divisors is an integer number (65501757526).
Almost surely, 2131003515051 is an apocalyptic number.
131003515051 is a deficient number, since it is larger than the sum of its proper divisors (1).
131003515051 is an equidigital number, since it uses as much as digits as its factorization.
131003515051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 131003515051 its reverse (150515300131), we get a palindrome (281518815182).
The spelling of 131003515051 in words is "one hundred thirty-one billion, three million, five hundred fifteen thousand, fifty-one".
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