1310042520535 has 16 divisors (see below), whose sum is σ = 1796866785792. Its totient is φ = 898196349600.

The previous prime is 1310042520509. The next prime is 1310042520583. The reversal of 1310042520535 is 5350252400131.

It is a de Polignac number, because none of the positive numbers 2^k-1310042520535 is a prime.

It is a super-2 number, since 2×1310042520535² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310042520497 and 1310042520506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2199721 + ... + 2731090.

It is an arithmetic number, because the mean of its divisors is an integer number (112304174112).

Almost surely, 2^{1310042520535} is an apocalyptic number.

1310042520535 is a deficient number, since it is larger than the sum of its proper divisors (486824265257).

1310042520535 is an equidigital number, since it uses as much as digits as its factorization.

1310042520535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4938414.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 1310042520535 its reverse (5350252400131), we get a palindrome (6660294920666).

The spelling of 1310042520535 in words is "one trillion, three hundred ten billion, forty-two million, five hundred twenty thousand, five hundred thirty-five".