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13100430000 = 24354762383
BaseRepresentation
bin11000011001101100…
…01011001010110000
31020210222202210112010
430030312023022300
5203312202230000
610003535402520
7642432550320
oct141466131260
936728683463
1013100430000
11561293aa59
122657383440
13130a136138
148c3c2d280
1551a18dd50
hex30cd8b2b0

13100430000 has 200 divisors, whose sum is σ = 48332128768. Its totient is φ = 2994336000.

The previous prime is 13100429987. The next prime is 13100430037. The reversal of 13100430000 is 3400131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 178809 + ... + 241191.

Almost surely, 213100430000 is an apocalyptic number.

13100430000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100430000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24166064384).

13100430000 is an abundant number, since it is smaller than the sum of its proper divisors (35231698768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100430000 is an equidigital number, since it uses as much as digits as its factorization.

13100430000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62421 (or 62400 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 13100430000 its reverse (3400131), we get a palindrome (13103830131).

The spelling of 13100430000 in words is "thirteen billion, one hundred million, four hundred thirty thousand".