Base | Representation |
---|---|
bin | 10011000100000101001… |
… | …011100111101100111011 |
3 | 11122020110202212210201201 |
4 | 103010011023213230323 |
5 | 132430441300120223 |
6 | 2441455103555031 |
7 | 163435210623166 |
oct | 23040513475473 |
9 | 4566422783651 |
10 | 1310051957563 |
11 | 4656541a4738 |
12 | 191a918bba77 |
13 | 966ca7a701b |
14 | 4759a594add |
15 | 24126647ead |
hex | 131052e7b3b |
1310051957563 has 2 divisors, whose sum is σ = 1310051957564. Its totient is φ = 1310051957562.
The previous prime is 1310051957537. The next prime is 1310051957567. The reversal of 1310051957563 is 3657591500131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310051957563 - 221 = 1310049860411 is a prime.
It is a super-2 number, since 2×13100519575632 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310051957567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655025978781 + 655025978782.
It is an arithmetic number, because the mean of its divisors is an integer number (655025978782).
Almost surely, 21310051957563 is an apocalyptic number.
1310051957563 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310051957563 is an equidigital number, since it uses as much as digits as its factorization.
1310051957563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 425250, while the sum is 46.
The spelling of 1310051957563 in words is "one trillion, three hundred ten billion, fifty-one million, nine hundred fifty-seven thousand, five hundred sixty-three".
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