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131010014041 = 235696087567
BaseRepresentation
bin111101000000011001…
…1100010101101011001
3110112011022110021102021
41322000303202231121
54121302030422131
6140103555134441
712315356513464
oct1720063425531
9415138407367
10131010014041
1150619812685
1221482ba4421
13c47b209a8a
1464ab6a22db
15361b871e11
hex1e80ce2b59

131010014041 has 4 divisors (see below), whose sum is σ = 136706101632. Its totient is φ = 125313926452.

The previous prime is 131010014017. The next prime is 131010014053. The reversal of 131010014041 is 140410010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010014041 - 29 = 131010013529 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010014341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848043761 + ... + 2848043806.

It is an arithmetic number, because the mean of its divisors is an integer number (34176525408).

Almost surely, 2131010014041 is an apocalyptic number.

It is an amenable number.

131010014041 is a deficient number, since it is larger than the sum of its proper divisors (5696087591).

131010014041 is an equidigital number, since it uses as much as digits as its factorization.

131010014041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5696087590.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 131010014041 its reverse (140410010131), we get a palindrome (271420024172).

The spelling of 131010014041 in words is "one hundred thirty-one billion, ten million, fourteen thousand, forty-one".

Divisors: 1 23 5696087567 131010014041