Base | Representation |
---|---|
bin | 11101110010011100101011… |
… | …000100011000110100010010 |
3 | 122011212102222211011221120012 |
4 | 131302130223010120310102 |
5 | 114132432201130003102 |
6 | 1142345114052514522 |
7 | 36411111441065363 |
oct | 3562345304306422 |
9 | 564772884157505 |
10 | 131010110000402 |
11 | 3882009173a056 |
12 | 1283a77891ba42 |
13 | 581427b273789 |
14 | 244cccd1ddb6a |
15 | 1022d1869a752 |
hex | 77272b118d12 |
131010110000402 has 4 divisors (see below), whose sum is σ = 196515165000606. Its totient is φ = 65505055000200.
The previous prime is 131010110000387. The next prime is 131010110000417. The reversal of 131010110000402 is 204000011010131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131010110000387) and next prime (131010110000417).
It can be written as a sum of positive squares in only one way, i.e., 125673090580801 + 5337019419601 = 11210401^2 + 2310199^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752527500099 + ... + 32752527500102.
Almost surely, 2131010110000402 is an apocalyptic number.
131010110000402 is a deficient number, since it is larger than the sum of its proper divisors (65505055000204).
131010110000402 is an equidigital number, since it uses as much as digits as its factorization.
131010110000402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65505055000203.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 131010110000402 its reverse (204000011010131), we get a palindrome (335010121010533).
The spelling of 131010110000402 in words is "one hundred thirty-one trillion, ten billion, one hundred ten million, four hundred two", and thus it is an aban number.
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