131010110000401 has 4 divisors (see below), whose sum is σ = 131030731777572. Its totient is φ = 130989488223232.

The previous prime is 131010110000387. The next prime is 131010110000417. The reversal of 131010110000401 is 104000011010131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 95880306838801 + 35129803161600 = 9791849^2 + 5927040^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010110000401 - 2¹¹ = 131010109998353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010110007401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10310879056 + ... + 10310891761.

It is an arithmetic number, because the mean of its divisors is an integer number (32757682944393).

Almost surely, 2^{131010110000401} is an apocalyptic number.

It is an amenable number.

131010110000401 is a deficient number, since it is larger than the sum of its proper divisors (20621777171).

131010110000401 is an equidigital number, since it uses as much as digits as its factorization.

131010110000401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20621777170.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 131010110000401 its reverse (104000011010131), we get a palindrome (235010121010532).

The spelling of 131010110000401 in words is "one hundred thirty-one trillion, ten billion, one hundred ten million, four hundred one", and thus it is an aban number.