131010111201401 has 2 divisors, whose sum is σ = 131010111201402. Its totient is φ = 131010111201400.

The previous prime is 131010111201391. The next prime is 131010111201407. The reversal of 131010111201401 is 104102111010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92256697351225 + 38753413850176 = 9605035^2 + 6225224^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010111201401 - 2⁴⁶ = 60641367023737 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131010111201401.

It is not a weakly prime, because it can be changed into another prime (131010111201407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505055600700 + 65505055600701.

It is an arithmetic number, because the mean of its divisors is an integer number (65505055600701).

Almost surely, 2^{131010111201401} is an apocalyptic number.

It is an amenable number.

131010111201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010111201401 is an equidigital number, since it uses as much as digits as its factorization.

131010111201401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 131010111201401 its reverse (104102111010131), we get a palindrome (235112222211532).

The spelling of 131010111201401 in words is "one hundred thirty-one trillion, ten billion, one hundred eleven million, two hundred one thousand, four hundred one".