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1310101153 is a prime number
BaseRepresentation
bin100111000010110…
…1000111010100001
310101022012000220221
41032011220322201
510140341214103
6334000003041
744315450614
oct11605507241
93338160827
101310101153
11612577429
12306900481
1317b5638aa
14c5dd017b
157a0381bd
hex4e168ea1

1310101153 has 2 divisors, whose sum is σ = 1310101154. Its totient is φ = 1310101152.

The previous prime is 1310101151. The next prime is 1310101181. The reversal of 1310101153 is 3511010131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 924646464 + 385454689 = 30408^2 + 19633^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310101153 - 21 = 1310101151 is a prime.

Together with 1310101151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1310101151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655050576 + 655050577.

It is an arithmetic number, because the mean of its divisors is an integer number (655050577).

Almost surely, 21310101153 is an apocalyptic number.

It is an amenable number.

1310101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310101153 is an equidigital number, since it uses as much as digits as its factorization.

1310101153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 16.

The square root of 1310101153 is about 36195.3194902324. The cubic root of 1310101153 is about 1094.2123434917.

Adding to 1310101153 its reverse (3511010131), we get a palindrome (4821111284).

The spelling of 1310101153 in words is "one billion, three hundred ten million, one hundred one thousand, one hundred fifty-three".