Base | Representation |
---|---|
bin | 11101110010011100101011… |
… | …101111001010010001001010 |
3 | 122011212110000121021121100200 |
4 | 131302130223233022101022 |
5 | 114132432212012304002 |
6 | 1142345115133113030 |
7 | 36411111635305233 |
oct | 3562345357122112 |
9 | 564773017247320 |
10 | 131010121213002 |
11 | 38820097aa8269 |
12 | 1283a780628776 |
13 | 581428069b255 |
14 | 244ccd08bc08a |
15 | 1022d19662b1c |
hex | 77272bbca44a |
131010121213002 has 12 divisors (see below), whose sum is σ = 283855262628210. Its totient is φ = 43670040404328.
The previous prime is 131010121212983. The next prime is 131010121213003. The reversal of 131010121213002 is 200312121010131.
131010121213002 is a `hidden beast` number, since 1 + 310 + 10 + 1 + 21 + 21 + 300 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 121026423442401 + 9983697770601 = 11001201^2 + 3159699^2 .
It is a super-3 number, since 3×1310101212130023 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 7278340067389 = 131010121213002 / (1 + 3 + 1 + 0 + 1 + 0 + 1 + 2 + 1 + 2 + 1 + 3 + 0 + 0 + 2).
It is not an unprimeable number, because it can be changed into a prime (131010121213003) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3639170033677 + ... + 3639170033712.
Almost surely, 2131010121213002 is an apocalyptic number.
131010121213002 is an abundant number, since it is smaller than the sum of its proper divisors (152845141415208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131010121213002 is a wasteful number, since it uses less digits than its factorization.
131010121213002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7278340067397 (or 7278340067394 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 131010121213002 its reverse (200312121010131), we get a palindrome (331322242223133).
The spelling of 131010121213002 in words is "one hundred thirty-one trillion, ten billion, one hundred twenty-one million, two hundred thirteen thousand, two".
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