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131010122031233 is a prime number
BaseRepresentation
bin11101110010011100101011…
…110010010010000010000001
3122011212110000122211011202112
4131302130223302102002001
5114132432212214444413
61142345115202425105
736411111645253604
oct3562345362220201
9564773018734675
10131010122031233
1138820098506a95
121283a780962195
1358142808c6803
14244ccd0a5233b
151022d197752a8
hex77272bc92081

131010122031233 has 2 divisors, whose sum is σ = 131010122031234. Its totient is φ = 131010122031232.

The previous prime is 131010122031227. The next prime is 131010122031251. The reversal of 131010122031233 is 332130221010131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114774968302864 + 16235153728369 = 10713308^2 + 4029287^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010122031233 - 218 = 131010121769089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131010122031199 and 131010122031208.

It is not a weakly prime, because it can be changed into another prime (131010122031203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505061015616 + 65505061015617.

It is an arithmetic number, because the mean of its divisors is an integer number (65505061015617).

Almost surely, 2131010122031233 is an apocalyptic number.

It is an amenable number.

131010122031233 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010122031233 is an equidigital number, since it uses as much as digits as its factorization.

131010122031233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 131010122031233 its reverse (332130221010131), we get a palindrome (463140343041364).

The spelling of 131010122031233 in words is "one hundred thirty-one trillion, ten billion, one hundred twenty-two million, thirty-one thousand, two hundred thirty-three".