Base | Representation |
---|---|
bin | 11101110010011100101100… |
… | …100000011001011110010110 |
3 | 122011212110001111120100220022 |
4 | 131302130230200121132112 |
5 | 114132432223313322332 |
6 | 1142345120313505142 |
7 | 36411112153104041 |
oct | 3562345440313626 |
9 | 564773044510808 |
10 | 131010134120342 |
11 | 388200a4313794 |
12 | 1283a784a121b2 |
13 | 581428326a229 |
14 | 244ccd24bbc58 |
15 | 1022d1a862212 |
hex | 77272c819796 |
131010134120342 has 4 divisors (see below), whose sum is σ = 196515201180516. Its totient is φ = 65505067060170.
The previous prime is 131010134120317. The next prime is 131010134120423. The reversal of 131010134120342 is 243021431010131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1310101341203422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752533530084 + ... + 32752533530087.
It is an arithmetic number, because the mean of its divisors is an integer number (49128800295129).
Almost surely, 2131010134120342 is an apocalyptic number.
131010134120342 is a deficient number, since it is larger than the sum of its proper divisors (65505067060174).
131010134120342 is an equidigital number, since it uses as much as digits as its factorization.
131010134120342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65505067060173.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 131010134120342 its reverse (243021431010131), we get a palindrome (374031565130473).
The spelling of 131010134120342 in words is "one hundred thirty-one trillion, ten billion, one hundred thirty-four million, one hundred twenty thousand, three hundred forty-two".
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