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131010144114347 is a prime number
BaseRepresentation
bin11101110010011100101101…
…000110100001011010101011
3122011212110002012101010002122
4131302130231012201122223
5114132432233343124342
61142345121312021455
736411112334050061
oct3562345506413253
9564773065333078
10131010144114347
11388200a9a1a3a3
121283a78823188b
135814285359144
14244ccd3960031
151022d1b6884d2
hex77272d1a16ab

131010144114347 has 2 divisors, whose sum is σ = 131010144114348. Its totient is φ = 131010144114346.

The previous prime is 131010144114319. The next prime is 131010144114467. The reversal of 131010144114347 is 743411441010131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131010144114347 - 210 = 131010144113323 is a prime.

It is a super-2 number, since 2×1310101441143472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131010144114247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505072057173 + 65505072057174.

It is an arithmetic number, because the mean of its divisors is an integer number (65505072057174).

Almost surely, 2131010144114347 is an apocalyptic number.

131010144114347 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010144114347 is an equidigital number, since it uses as much as digits as its factorization.

131010144114347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 35.

Adding to 131010144114347 its reverse (743411441010131), we get a palindrome (874421585124478).

The spelling of 131010144114347 in words is "one hundred thirty-one trillion, ten billion, one hundred forty-four million, one hundred fourteen thousand, three hundred forty-seven".