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131010202221 = 343670067407
BaseRepresentation
bin111101000000011010…
…0010000101001101101
3110112011022210211112220
41322000310100221231
54121302102432341
6140104003145553
712315361226223
oct1720064205155
9415138724486
10131010202221
1150619930aa8
12214830752b9
13c47b274622
1464ab710b13
15361b8aca66
hex1e80d10a6d

131010202221 has 4 divisors (see below), whose sum is σ = 174680269632. Its totient is φ = 87340134812.

The previous prime is 131010202201. The next prime is 131010202261. The reversal of 131010202221 is 122202010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010202221 - 26 = 131010202157 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131010202221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010202201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21835033701 + ... + 21835033706.

It is an arithmetic number, because the mean of its divisors is an integer number (43670067408).

Almost surely, 2131010202221 is an apocalyptic number.

It is an amenable number.

131010202221 is a deficient number, since it is larger than the sum of its proper divisors (43670067411).

131010202221 is an equidigital number, since it uses as much as digits as its factorization.

131010202221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43670067410.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 131010202221 its reverse (122202010131), we get a palindrome (253212212352).

The spelling of 131010202221 in words is "one hundred thirty-one billion, ten million, two hundred two thousand, two hundred twenty-one".

Divisors: 1 3 43670067407 131010202221