Base | Representation |
---|---|
bin | 111101000000011010… |
… | …0010010111000000011 |
3 | 110112011022211022001022 |
4 | 1322000310102320003 |
5 | 4121302103230311 |
6 | 140104003300055 |
7 | 12315361264616 |
oct | 1720064227003 |
9 | 415138738038 |
10 | 131010211331 |
11 | 5061993792a |
12 | 2148307a62b |
13 | c47b27880c |
14 | 64ab71417d |
15 | 361b8b05db |
hex | 1e80d12e03 |
131010211331 has 4 divisors (see below), whose sum is σ = 131277035064. Its totient is φ = 130743387600.
The previous prime is 131010211303. The next prime is 131010211361. The reversal of 131010211331 is 133112010131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 133112010131 = 17 ⋅7830118243.
It is a cyclic number.
It is not a de Polignac number, because 131010211331 - 210 = 131010210307 is a prime.
It is a super-2 number, since 2×1310102113312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131010211361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133411130 + ... + 133412111.
It is an arithmetic number, because the mean of its divisors is an integer number (32819258766).
Almost surely, 2131010211331 is an apocalyptic number.
131010211331 is a deficient number, since it is larger than the sum of its proper divisors (266823733).
131010211331 is an equidigital number, since it uses as much as digits as its factorization.
131010211331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266823732.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131010211331 its reverse (133112010131), we get a palindrome (264122221462).
The spelling of 131010211331 in words is "one hundred thirty-one billion, ten million, two hundred eleven thousand, three hundred thirty-one".
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