Base | Representation |
---|---|
bin | 11101110010011100110001… |
… | …001001100100011101111111 |
3 | 122011212110020221011012002012 |
4 | 131302130301021210131333 |
5 | 114132432403234202033 |
6 | 1142345132135321435 |
7 | 36411114120211016 |
oct | 3562346111443577 |
9 | 564773227135065 |
10 | 131010212022143 |
11 | 38820134291543 |
12 | 1283a7a6b2027b |
13 | 581429644457c |
14 | 244ccdc999a7d |
15 | 1022d225ee248 |
hex | 77273126477f |
131010212022143 has 16 divisors (see below), whose sum is σ = 136452781025280. Its totient is φ = 125667910720800.
The previous prime is 131010212022127. The next prime is 131010212022167. The reversal of 131010212022143 is 341220212010131.
It is a cyclic number.
It is not a de Polignac number, because 131010212022143 - 24 = 131010212022127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131010212022343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53010488 + ... + 55426818.
It is an arithmetic number, because the mean of its divisors is an integer number (8528298814080).
Almost surely, 2131010212022143 is an apocalyptic number.
131010212022143 is a deficient number, since it is larger than the sum of its proper divisors (5442569003137).
131010212022143 is a wasteful number, since it uses less digits than its factorization.
131010212022143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2437078.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 131010212022143 its reverse (341220212010131), we get a palindrome (472230424032274).
The spelling of 131010212022143 in words is "one hundred thirty-one trillion, ten billion, two hundred twelve million, twenty-two thousand, one hundred forty-three".
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