Base | Representation |
---|---|
bin | 10011000100001000001… |
… | …110010101001110100001 |
3 | 11122020121022221000202012 |
4 | 103010020032111032201 |
5 | 132431042331444334 |
6 | 2441504130002305 |
7 | 163436400521651 |
oct | 23041016251641 |
9 | 4566538830665 |
10 | 1310102999969 |
11 | 46567aa97645 |
12 | 191aa6a16395 |
13 | 96708238a2a |
14 | 475a3280361 |
15 | 2412ad7b9ce |
hex | 131083953a1 |
1310102999969 has 2 divisors, whose sum is σ = 1310102999970. Its totient is φ = 1310102999968.
The previous prime is 1310102999941. The next prime is 1310102999983. The reversal of 1310102999969 is 9699992010131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 911620124944 + 398482875025 = 954788^2 + 631255^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310102999969 - 240 = 210591372193 is a prime.
It is a super-2 number, since 2×13101029999692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310102999069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051499984 + 655051499985.
It is an arithmetic number, because the mean of its divisors is an integer number (655051499985).
Almost surely, 21310102999969 is an apocalyptic number.
It is an amenable number.
1310102999969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310102999969 is an equidigital number, since it uses as much as digits as its factorization.
1310102999969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2125764, while the sum is 59.
The spelling of 1310102999969 in words is "one trillion, three hundred ten billion, one hundred two million, nine hundred ninety-nine thousand, nine hundred sixty-nine".
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