Base | Representation |
---|---|
bin | 10011000100001000001… |
… | …110010101001110101111 |
3 | 11122020121022221000202201 |
4 | 103010020032111032233 |
5 | 132431042331444413 |
6 | 2441504130002331 |
7 | 163436400522001 |
oct | 23041016251657 |
9 | 4566538830681 |
10 | 1310102999983 |
11 | 46567aa97658 |
12 | 191aa6a163a7 |
13 | 96708238a3b |
14 | 475a3280371 |
15 | 2412ad7b9dd |
hex | 131083953af |
1310102999983 has 2 divisors, whose sum is σ = 1310102999984. Its totient is φ = 1310102999982.
The previous prime is 1310102999969. The next prime is 1310103000043. The reversal of 1310102999983 is 3899992010131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310102999983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310102939983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051499991 + 655051499992.
It is an arithmetic number, because the mean of its divisors is an integer number (655051499992).
Almost surely, 21310102999983 is an apocalyptic number.
1310102999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310102999983 is an equidigital number, since it uses as much as digits as its factorization.
1310102999983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 944784, while the sum is 55.
The spelling of 1310102999983 in words is "one trillion, three hundred ten billion, one hundred two million, nine hundred ninety-nine thousand, nine hundred eighty-three".
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