131010311330113 has 4 divisors (see below), whose sum is σ = 131022597780928. Its totient is φ = 130998024879300.

The previous prime is 131010311330071. The next prime is 131010311330117. The reversal of 131010311330113 is 311033113010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010311330113 - 2¹⁷ = 131010311199041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010311330117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6143209413 + ... + 6143230738.

It is an arithmetic number, because the mean of its divisors is an integer number (32755649445232).

Almost surely, 2^{131010311330113} is an apocalyptic number.

It is an amenable number.

131010311330113 is a deficient number, since it is larger than the sum of its proper divisors (12286450815).

131010311330113 is a wasteful number, since it uses less digits than its factorization.

131010311330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12286450814.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 131010311330113 its reverse (311033113010131), we get a palindrome (442043424340244).

The spelling of 131010311330113 in words is "one hundred thirty-one trillion, ten billion, three hundred eleven million, three hundred thirty thousand, one hundred thirteen".