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131010340204141 is a prime number
BaseRepresentation
bin11101110010011100111000…
…110010100010111001101101
3122011212110120212100111201121
4131302130320302202321231
5114132433134043013031
61142345152554540541
736411120234560326
oct3562347062427155
9564773525314647
10131010340204141
113882019a681582
121283a821a37751
1358142b6b746c8
14244cd11a0544d
151022d2d9be011
hex772738ca2e6d

131010340204141 has 2 divisors, whose sum is σ = 131010340204142. Its totient is φ = 131010340204140.

The previous prime is 131010340204127. The next prime is 131010340204151. The reversal of 131010340204141 is 141402043010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111628818226116 + 19381521978025 = 10565454^2 + 4402445^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010340204141 - 213 = 131010340195949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131010340204111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505170102070 + 65505170102071.

It is an arithmetic number, because the mean of its divisors is an integer number (65505170102071).

Almost surely, 2131010340204141 is an apocalyptic number.

It is an amenable number.

131010340204141 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010340204141 is an equidigital number, since it uses as much as digits as its factorization.

131010340204141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131010340204141 its reverse (141402043010131), we get a palindrome (272412383214272).

The spelling of 131010340204141 in words is "one hundred thirty-one trillion, ten billion, three hundred forty million, two hundred four thousand, one hundred forty-one".