Base | Representation |
---|---|
bin | 11101110010011100111000… |
… | …110010100010111001101101 |
3 | 122011212110120212100111201121 |
4 | 131302130320302202321231 |
5 | 114132433134043013031 |
6 | 1142345152554540541 |
7 | 36411120234560326 |
oct | 3562347062427155 |
9 | 564773525314647 |
10 | 131010340204141 |
11 | 3882019a681582 |
12 | 1283a821a37751 |
13 | 58142b6b746c8 |
14 | 244cd11a0544d |
15 | 1022d2d9be011 |
hex | 772738ca2e6d |
131010340204141 has 2 divisors, whose sum is σ = 131010340204142. Its totient is φ = 131010340204140.
The previous prime is 131010340204127. The next prime is 131010340204151. The reversal of 131010340204141 is 141402043010131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111628818226116 + 19381521978025 = 10565454^2 + 4402445^2 .
It is a cyclic number.
It is not a de Polignac number, because 131010340204141 - 213 = 131010340195949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131010340204111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505170102070 + 65505170102071.
It is an arithmetic number, because the mean of its divisors is an integer number (65505170102071).
Almost surely, 2131010340204141 is an apocalyptic number.
It is an amenable number.
131010340204141 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010340204141 is an equidigital number, since it uses as much as digits as its factorization.
131010340204141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 131010340204141 its reverse (141402043010131), we get a palindrome (272412383214272).
The spelling of 131010340204141 in words is "one hundred thirty-one trillion, ten billion, three hundred forty million, two hundred four thousand, one hundred forty-one".
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