Base | Representation |
---|---|
bin | 1011111010100101001100… |
… | …0000111010011111110111 |
3 | 1201101110002012201211101021 |
4 | 2332221103000322133313 |
5 | 3204121414002020320 |
6 | 43510311442442011 |
7 | 2521343026056202 |
oct | 276512300723767 |
9 | 51343065654337 |
10 | 13101043001335 |
11 | 41a113725a173 |
12 | 15770a0963307 |
13 | 7405665ac9c3 |
14 | 3341457c8939 |
15 | 17abc5248daa |
hex | bea5303a7f7 |
13101043001335 has 16 divisors (see below), whose sum is σ = 15824122899840. Its totient is φ = 10412364967200.
The previous prime is 13101043001329. The next prime is 13101043001353. The reversal of 13101043001335 is 53310034010131.
It is not a de Polignac number, because 13101043001335 - 221 = 13101040904183 is a prime.
It is a super-3 number, since 3×131010430013353 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6023217 + ... + 7904506.
It is an arithmetic number, because the mean of its divisors is an integer number (989007681240).
Almost surely, 213101043001335 is an apocalyptic number.
13101043001335 is a deficient number, since it is larger than the sum of its proper divisors (2723079898505).
13101043001335 is a wasteful number, since it uses less digits than its factorization.
13101043001335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13928958.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 13101043001335 its reverse (53310034010131), we get a palindrome (66411077011466).
The spelling of 13101043001335 in words is "thirteen trillion, one hundred one billion, forty-three million, one thousand, three hundred thirty-five".
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