Base | Representation |
---|---|
bin | 11101110010011100111110… |
… | …101111101111001010111101 |
3 | 122011212110211211101022222001 |
4 | 131302130332233233022331 |
5 | 114132433340133200021 |
6 | 1142345210524422301 |
7 | 36411122560130125 |
oct | 3562347657571275 |
9 | 564773754338861 |
10 | 131010440131261 |
11 | 38820241023279 |
12 | 1283a84b3a7991 |
13 | 5814301790c92 |
14 | 244cd20db7c85 |
15 | 1022d3765c091 |
hex | 77273ebef2bd |
131010440131261 has 2 divisors, whose sum is σ = 131010440131262. Its totient is φ = 131010440131260.
The previous prime is 131010440131229. The next prime is 131010440131283. The reversal of 131010440131261 is 162131044010131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111854018123236 + 19156422008025 = 10576106^2 + 4376805^2 .
It is a cyclic number.
It is not a de Polignac number, because 131010440131261 - 25 = 131010440131229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131010440131211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505220065630 + 65505220065631.
It is an arithmetic number, because the mean of its divisors is an integer number (65505220065631).
Almost surely, 2131010440131261 is an apocalyptic number.
It is an amenable number.
131010440131261 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010440131261 is an equidigital number, since it uses as much as digits as its factorization.
131010440131261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 131010440131261 its reverse (162131044010131), we get a palindrome (293141484141392).
The spelling of 131010440131261 in words is "one hundred thirty-one trillion, ten billion, four hundred forty million, one hundred thirty-one thousand, two hundred sixty-one".
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